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Multi-Step Equations
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Question 1 of 7
1. Question
Solve`4/5 x-9=-1`- `x=` (10)
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Inverse Operations
When moving a term to the other side of an equation, the operation is inversed.To solve for `x`, it needs to be alone on one side.Start by moving `-9` to the other side by adding `9` to both sides of the equation.`4/5``x` `-9` `=` `-1` `4/5``x` `-9` `+9` `=` `-1` `+9` `4/5``x` `=` `8` `-9+9` cancels out Next, remove `1/5` by multiplying both sides of the equation by `5`.`4/5``x` `=` `8` `4/5``x``times5` `=` `8``times5` `4``x` `=` `40` `1/5 times5` cancels out Finally, remove `4` by dividing both sides of the equation by `4`.`4``x` `=` `40` `4``x``divide4` `=` `40``divide4` `x` `=` `10` `4divide4` cancels out Check our workTo confirm our answer, substitute `x=10` to the original equation.`4/5 x-9` `=` `-1` `4/5 (10)-9` `=` `-1` Substitute `x=10` `40/5-9` `=` `-1` `8-9` `=` `-1` `-1` `=` `-1` Since the equation is true, the answer is correct.`x=10`Hint
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Question 2 of 7
2. Question
Solve`(2m)/3+8=10`- `m=` (3)
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Inverse Operations
When moving a term to the other side of an equation, the operation is inversed.To solve for `m`, it needs to be alone on one side.Start by moving `8` to the other side by subtracting `8` from both sides of the equation.$$\frac{2\color{#00880A}{m}}{3}+8$$ `=` `10` $$\frac{2\color{#00880A}{m}}{3}+8 \color{#CC0000}{-8}$$ `=` `10` `-8` $$\frac{2\color{#00880A}{m}}{3}$$ `=` `2` `8-8` cancels out Next, remove `1/3` by multiplying both sides of the equation by `3`.$$\frac{2\color{#00880A}{m}}{3}$$ `=` `2` $$\frac{2\color{#00880A}{m}}{3} \color{#CC0000}{\times3}$$ `=` `2``times3` `2``m` `=` `6` `1/3 times3` cancels out Finally, remove `2` by dividing both sides of the equation by `2`.`2``m` `=` `6` `2``m``divide2` `=` `6``divide2` `m` `=` `3` `2divide2` cancels out Check our workTo confirm our answer, substitute `m=3` to the original equation.`(2m)/3+8` `=` `10` `(2(3))/3+8` `=` `10` Substitute `m=3` `6/3+8` `=` `10` `2+8` `=` `10` `10` `=` `10` Since the equation is true, the answer is correct.`m=3`Hint
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Question 3 of 7
3. Question
Solve for `x``(x-4)/2=3`- `x=` (10)
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Help VideoTo solve for `x`, get `x` by itselfMultiply both sides of the equation by `2``frac{x-4}{2}``times2` `=` `3``times2` `frac{2(x-4)}{2}` `=` `3``times2` `x-4` `=` `6` The coefficient `2/2` cancels out Finally, add `4` to both sides of the equation`x-4` `+4` `=` `6` `+4` `x``-4` `+4` `=` `6` `+4` `-4+4` cancels out `x` `=` `10` `x=10`Hint
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Question 4 of 7
4. Question
Solve for `x``(9+x)/3=5`- `x=` (6)
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Exceptional!
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To solve for `x`, get `x` by itselfMultiply both sides of the equation by `3``(9+x)/3``xx 3` `=` `5``xx 3` `(3(9+x))/3` `=` `5``xx 3` `9+x` `=` `15` The coefficient `3/3` cancels out Finally, subtract `9` from both sides of the equation`9+x` `-9` `=` `15` `-9` `9``+x` `-9` `=` `15` `-9` `9-9` cancels out `x` `=` `6` `x=6` -
Question 5 of 7
5. Question
Solve`(4-4z)/2=8`- `z=` (-3)
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Inverse Operations
When moving a term to the other side of an equation, the operation is inversed.To solve for `z`, it needs to be alone on one side.Start with removing `1/2` by multiplying both sides of the equation by `2`.$$\frac{4-4\color{#00880A}{z}}{2}$$ `=` `8` $$\frac{4-4\color{#00880A}{z}}{2}\color{#CC0000}{\times2}$$ `=` `8``times2` `4-4``z` `=` `16` `1/2 times2` cancels out Next, move `4` to the other side by subtracting `4` from both sides of the equation.`4-4``z` `=` `16` `4-4``z` `-4` `=` `16` `-4` `-4``z` `=` `12` `4-4` cancels out Finally, remove `-4` by dividing both sides of the equation by `-4`.`-4``z` `=` `12` `-4``z``divide-4` `=` `12``divide-4` `z` `=` `-3` `-4divide-4` cancels out Check our workTo confirm our answer, substitute `z=-3` to the original equation.`(4-4z)/2` `=` `8` `(4-4(-3))/2` `=` `8` Substitute `z=-3` `(4+12)/2` `=` `8` `16/2` `=` `8` `8` `=` `8` Since the equation is true, the answer is correct.`z=-3`Hint
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Question 6 of 7
6. Question
Solve`(3y+4)/(-2)=7`- `y=` (-6)
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Inverse Operations
When moving a term to the other side of an equation, the operation is inversed.To solve for `y`, it needs to be alone on one side.Start with removing `1/(-2)` by multiplying both sides of the equation by `-2`.$$\frac{3\color{#00880A}{y}+4}{-2}$$ `=` `7` $$\frac{3\color{#00880A}{y}+4}{-2}\color{#CC0000}{\times(-2)}$$ `=` `7``times(-2)` `3``y` `+4` `=` `-14` `1/(-2) times(-2)` cancels out Next, move `4` to the other side by subtracting `4` from both sides of the equation.`3``y` `+4` `=` `-14` `3``y` `+4` `-4` `=` `-14` `-4` `3``y` `=` `-18` `4-4` cancels out Finally, remove `3` by dividing both sides of the equation by `3`.`3``y` `=` `-18` `3``y``divide3` `=` `-18``divide3` `y` `=` `-6` `3divide3` cancels out Check our workTo confirm our answer, substitute `y=-6` to the original equation.`(3y+4)/(-2)` `=` `7` `(3(-6)+4)/(-2)` `=` `7` Substitute `y=-6` `(-18+4)/(-2)` `=` `7` `(-14)/(-2)` `=` `7` `7` `=` `7` Since the equation is true, the answer is correct.`y=-6`Hint
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Question 7 of 7
7. Question
Solve`(8x-2)/(-5)=-6`- `x=` (4)
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Keep Going!
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Inverse Operations
When moving a term to the other side of an equation, the operation is inversed.To solve for `x`, it needs to be alone on one side.Start with removing `1/(-5)` by multiplying both sides of the equation by `-5`.$$\frac{8\color{#00880A}{x}-2}{-5}$$ `=` `-6` $$\frac{8\color{#00880A}{x}-2}{-5}\color{#CC0000}{\times(-5)}$$ `=` `-6``times(-5)` `8``x` `-2` `=` `30` `1/(-5) times(-5)` cancels out Next, move `-2` to the other side by adding `2` to both sides of the equation.`8``x` `-2` `=` `30` `8``x` `-2` `+2` `=` `30` `+2` `8``x` `=` `32` `-2+2` cancels out Finally, remove `8` by dividing both sides of the equation by `8`.`8``x` `=` `32` `8``x``divide8` `=` `32``divide8` `x` `=` `4` `8divide8` cancels out Check our workTo confirm our answer, substitute `x=4` to the original equation.`(8x-2)/(-5)` `=` `-6` `(8(4)-2)/(-5)` `=` `-6` Substitute `x=4` `(32-2)/(-5)` `=` `-6` `(30)/(-5)` `=` `-6` `-6` `=` `-6` Since the equation is true, the answer is correct.`x=4`Hint
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- One Step Equations – Add and Subtract
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- Two Step Equations
- Multi-Step Equations
- Solve Equations using the Distributive Property
- Equations with Variables on Both Sides
- Equations with Variables on Both Sides (Fractions)
- Solve Equations with Variables on Both Sides using the Distributive Property
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