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Two Step Equations

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  1. Question 1 of 21
    1. Question
    Solve
    `2m+8=12`
    • `m=` (2)
    Correct

    Excellent!

    Incorrect

    Help Video
     
    Inverse Operations
    When moving a term to the other side of an equation, the operation is inversed.
    To solve for `m`, it needs to be alone on one side.
    Start by moving `8` to the other side by subtracting `8` from both sides of the equation.
    `2``m` `+8` `=` `12`
    `2``m` `+8` `-8` `=` `12` `-8`
    `2``m` `=` `4` `8-8` cancels out
    Next, remove `2` by dividing both sides of the equation by `2`.
    `2``m` `=` `4`
    `2``m``-:2` `=` `4``-:2`
    `m` `=` `2` `2-:2` cancels out
    Check our work
    To confirm our answer, substitute `m=2` to the original equation.
    `2m+8` `=` `12`
    `2(2)+8` `=` `12` Substitute `m=2`
    `4+8` `=` `12`
    `12` `=` `12`
    Since the equation is true, the answer is correct.
    `m=2`

    Hint
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  2. Question 2 of 21
    2. Question
    Solve
    `5-2u=11`
    • `u=` (-3)
    Correct

    Good Job!

    Incorrect

    Help Video
     
    Inverse Operations
    When moving a term to the other side of an equation, the operation is inversed.
    To solve for `u`, it needs to be alone on one side.
    Start by moving `5` to the other side by subtracting `5` from both sides of the equation.
    `5-2``u` `=` `11`
    `5-2``u` `-5` `=` `11` `-5`
    `-2``u` `=` `6` `5-5` cancels out
    Next, remove `-2` by dividing both sides of the equation by `-2`.
    `-2``u` `=` `6`
    `-2``u``-:-2` `=` `6``-:-2`
    `u` `=` `-3` `-2-:-2` cancels out
    Check our work
    To confirm our answer, substitute `u=-3` to the original equation.
    `5-2u` `=` `11`
    `5-2(-3)` `=` `11` Substitute `u=-3`
    `5+6` `=` `11`
    `11` `=` `11`
    Since the equation is true, the answer is correct.
    `u=-3`

    Hint
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  3. Question 3 of 21
    3. Question
    Solve
    `4n-26=-2`
    • `n=` (6)
    Correct

    Fantastic!

    Incorrect

    Help Video
     
    Inverse Operations
    When moving a term to the other side of an equation, the operation is inversed.
    To solve for `n`, it needs to be alone on one side.
    Start by moving `26` to the other side by adding `26` to both sides of the equation.
    `4``n` `-26` `=` `-2`
    `4``n` `-26` `+26` `=` `-2` `+26`
    `4``n` `=` `24` `-26+26` cancels out
    Next, remove `4` by dividing both sides of the equation by `4`.
    `4``n` `=` `24`
    `4``n``-:4` `=` `24``-:4`
    `n` `=` `6` `4-:4` cancels out
    Check our work
    To confirm our answer, substitute `n=6` to the original equation.
    `4n-26` `=` `-2`
    `4(6)-26` `=` `-2` Substitute `n=6`
    `24-26` `=` `-2`
    `-2` `=` `-2`
    Since the equation is true, the answer is correct.
    `n=6`

    Hint
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  4. Question 4 of 21
    4. Question
    Solve
    `3a+4=-8`
    • `a=` (-4)
    Correct

    Great Work!

    Incorrect

    Help Video
     
    Inverse Operations
    When moving a term to the other side of an equation, the operation is inversed.
    To solve for `a`, it needs to be alone on one side.
    Start by moving `4` to the other side by subtracting `4` from both sides of the equation.
    `3``a` `+4` `=` `-8`
    `3``a` `+4` `-4` `=` `-8` `-4`
    `3``a` `=` `-12` `4-4` cancels out
    Next, remove `3` by dividing both sides of the equation by `3`.
    `3``a` `=` `-12`
    `3``a``-:3` `=` `-12``-:3`
    `a` `=` `-4` `3-:3` cancels out
    Check our work
    To confirm our answer, substitute `a=-4` to the original equation.
    `3a+4` `=` `-8`
    `3(-4)+4` `=` `-8` Substitute `a=-4`
    `-12+4` `=` `-8`
    `-8` `=` `-8`
    Since the equation is true, the answer is correct.
    `a=-4`

    Hint
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  5. Question 5 of 21
    5. Question
    Solve
    `-7x+8=-6`
    • `x=` (2)
    Correct

    Well Done!

    Incorrect

    Help Video
     
    Inverse Operations
    When moving a term to the other side of an equation, the operation is inversed.
    To solve for `x`, it needs to be alone on one side.
    Start by moving `8` to the other side by subtracting `8` from both sides of the equation.
    `-7``x` `+8` `=` `-6`
    `-7``x` `+8` `-8` `=` `-6` `-8`
    `-7``x` `=` `-14` `8-8` cancels out
    Next, remove `-7` by dividing both sides of the equation by `-7`.
    `-7``x` `=` `-14`
    `-7``x``-:-7` `=` `-14``-:-7`
    `x` `=` `2` `-7-:-7` cancels out
    Check our work
    To confirm our answer, substitute `x=2` to the original equation.
    `-7x+8` `=` `-6`
    `-7(2)+8` `=` `-6` Substitute `x=2`
    `-14+8` `=` `-6`
    `-6` `=` `-6`
    Since the equation is true, the answer is correct.
    `x=2`

    Hint
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  6. Question 6 of 21
    6. Question
    Solve
    `-2y-13=-11`
    • `y=` (-1)
    Correct

    Fantastic!

    Incorrect

    Help Video
     
    Inverse Operations
    When moving a term to the other side of an equation, the operation is inversed.
    To solve for `y`, it needs to be alone on one side.
    Start by moving `13` to the other side by adding `13` to both sides of the equation.
    `-2``y` `-13` `=` `-11`
    `-2``y` `-13` `+13` `=` `-11` `+13`
    `-2``y` `=` `2` `-13+13` cancels out
    Next, remove `-2` by dividing both sides of the equation by `-2`.
    `-2``y` `=` `2`
    `-2``y``-:-2` `=` `2``-:-2`
    `y` `=` `-1` `-2-:-2` cancels out
    Check our work
    To confirm our answer, substitute `y=-1` to the original equation.
    `-2y-13` `=` `-11`
    `-2(-1)-13` `=` `-11` Substitute `y=-1`
    `2-13` `=` `-11`
    `-11` `=` `-11`
    Since the equation is true, the answer is correct.
    `y=-1`

    Hint
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  7. Question 7 of 21
    7. Question
    Solve for `x`
    `2x+4=16`
    • `x=` (6)
    Correct

    Nice Job!

    Incorrect

    Help Video
     
    To solve for `x`, get `x` by itself
    Subtract `4` from both sides of the equation
    `2x+4` `-4` `=` `16` `-4`
    `2x``+4``-4` `=` `16` `-4` `4-4` cancels out
    `2x` `=` `12`
    Finally, divide both sides of the equation by `2`
    `2x``divide2` `=` `12``divide2`
    `2``x``divide2` `=` `12``divide2` `times2divide2` cancels out
    `x` `=` `6`
    `x=6`

    Hint
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  8. Question 8 of 21
    8. Question
    Solve for `x`
    `1-3x=7`
    • `x=` (-2)
    Correct

    Fantastic!

    Incorrect

    Help Video
     
    To solve for `x`, get `x` by itself
    Subtract `1` from both sides of the equation
    `1-3x` `-1` `=` `7` `-1`
    `1``-3x` `-1` `=` `7` `-1` `1-1` cancels out
    `-3x` `=` `6`
    Finally, divide both sides of the equation by `-3`
    `-3x``divide(-3)` `=` `6``divide(-3)`
    `-3``x``divide(-3)` `=` `6``divide(-3)` `times(-3)divide(-3)` cancels out
    `x` `=` `-2`
    `x=-2`

    Hint
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  9. Question 9 of 21
    9. Question
    Solve for `x`
    `3x+7=19`
    • `x=` (4)
    Correct

    Correct!

    Incorrect

    To solve for `x`, get `x` by itself
    Subtract `7` from both sides of the equation
    `3x+7` `-7` `=` `19` `-7`
    `3x``+7` `-7` `=` `19` `-7` `7-7` cancels out
    `3x` `=` `12`
    Finally, divide both sides of the equation by `3`
    `3x``divide3` `=` `12``divide3`
    `3``x``divide3` `=` `12``divide3` `times3divide3` cancels out
    `x` `=` `4`
    `x=4`

  10. Question 10 of 21
    10. Question
    Solve for `m`
    `2m+9=23`
    • `m=` (7)
    Correct

    Great Work!

    Incorrect

    Help Video
     
    To solve for `m`, get `m` by itself
    Subtract `9` from both sides of the equation
    `2m+9` `-9` `=` `23` `-9`
    `2m``+9` `-9` `=` `23` `-9` `9-9` cancels out
    `2m` `=` `14`
    Finally, divide both sides of the equation by `2`
    `2m``divide2` `=` `14``divide2`
    `2``m``divide2` `=` `14``divide2` `times2divide2` cancels out
    `m` `=` `7`
    `m=7`

    Hint
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  11. Question 11 of 21
    11. Question
    Solve for `a`
    `3a+5=-10`
    • `a=` (-5)
    Correct

    Keep Going!

    Incorrect

    Help Video
     
    To solve for `a`, get `a` by itself
    Subtract `5` from both sides of the equation
    `3a+5` `-5` `=` `-10` `-5`
    `3a``+5` `-5` `=` `-10` `-5` `5-5` cancels out
    `3a` `=` `-15`
    Finally, divide both sides of the equation by `3`
    `3a``divide3` `=` `-15``divide3`
    `3``a``divide3` `=` `-15``divide3` `times3divide3` cancels out
    `a` `=` `-5`
    `a=-5`

    Hint
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  12. Question 12 of 21
    12. Question
    Solve for `p`
    `-1+5p=-16`
    • `p=` (-3)
    Correct

    Excellent!

    Incorrect

    To solve for `p`, get `p` by itself
    Add `1` to both sides of the equation
    `-1+5p` `+1` `=` `-16` `+1`
    `-1``+5p` `+1` `=` `-16` `+1` `-1+1` cancels out
    `5p` `=` `-15`
    Finally, divide both sides of the equation by `5`
    `5p``-:5` `=` `-15``-:5`
    `5``p``divide5` `=` `-15``-:5` `times5divide5` cancels out
    `p` `=` `-3`
    `p=-3`

  13. Question 13 of 21
    13. Question
    Solve for `r`
    `-4r-1=31`
    • `r=` (-8)
    Correct

    Well Done!

    Incorrect

    To solve for `r`, get `r` by itself
    Add `1` to both sides of the equation
    `-4r-1``+1` `=` `31``+1`
    `-4r``-1``+1` `=` `32` `-1+1` cancels out
    `-4r` `=` `32`
    Finally, divide both sides of the equation by `-4`
    `-4r``divide -4` `=` `32``divide -4`
    `-4``r``divide -4` `=` `-8` `-4 divide -4` cancels out
    `r` `=` `-8`
    `r=-8`

  14. Question 14 of 21
    14. Question
    Solve
    `x/3 +4=7`
    • `x=` (9)
    Correct

    Good Job!

    Incorrect

    Help Video
     
    Inverse Operations
    When moving a term to the other side of an equation, the operation is inversed.
    To solve for `x`, it needs to be alone on one side.
    Start by moving `4` to the other side by subtracting `4` from both sides of the equation.
    $$\frac{\color{#00880A}{x}}{3}+4$$ `=` `7`
    $$\frac{\color{#00880A}{x}}{3}+4\color{#CC0000}{-4}$$ `=` `7` `-4`
    $$\frac{\color{#00880A}{x}}{3}$$ `=` `3` `4-4` cancels out
    Next, remove `1/3` by multiplying both sides of the equation by `3`.
    $$\frac{\color{#00880A}{x}}{3}$$ `=` `3`
    $$\frac{\color{#00880A}{x}}{3}\color{#CC0000}{\times3}$$ `=` `3``xx3`
    `x` `=` `9` `1/3 times3` cancels out
    Check our work
    To confirm our answer, substitute `x=9` to the original equation.
    `x/3 +4` `=` `7`
    `9/3 +4` `=` `7` Substitute `x=9`
    `3+4` `=` `7`
    `7` `=` `7`
    Since the equation is true, the answer is correct.
    `x=9`

    Hint
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  15. Question 15 of 21
    15. Question
    Solve
    `x/7 +3=-2`
    • `x=` (-35)
    Correct

    Great Work!

    Incorrect

    Help Video
     
    Inverse Operations
    When moving a term to the other side of an equation, the operation is inversed.
    To solve for `x`, it needs to be alone on one side.
    Start by moving `3` to the other side by subtracting `3` from both sides of the equation.
    $$\frac{\color{#00880A}{x}}{7}+3$$ `=` `-2`
    $$\frac{\color{#00880A}{x}}{7}+3\color{#CC0000}{-3}$$ `=` `-2` `-3`
    $$\frac{\color{#00880A}{x}}{7}$$ `=` `-5` `3-3` cancels out
    Next, remove `1/7` by multiplying both sides of the equation by `7`.
    $$\frac{\color{#00880A}{x}}{7}$$ `=` `-5`
    $$\frac{\color{#00880A}{x}}{7}\color{#CC0000}{\times7}$$ `=` `-5``xx7`
    `x` `=` `-35` `1/7 times7` cancels out
    Check our work
    To confirm our answer, substitute `x=-35` to the original equation.
    `x/7 +3` `=` `-2`
    `(-35)/7 +3` `=` `-2` Substitute `x=-35`
    `-5+3` `=` `-2`
    `-2` `=` `-2`
    Since the equation is true, the answer is correct.
    `x=-35`

    Hint
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  16. Question 16 of 21
    16. Question
    Solve
    `t/5 -3=-6`
    • `t=` (-15)
    Correct

    Excellent!

    Incorrect

    Help Video
     
    Inverse Operations
    When moving a term to the other side of an equation, the operation is inversed.
    To solve for `t`, it needs to be alone on one side.
    Start by moving `3` to the other side by adding `3` to both sides of the equation.
    $$\frac{\color{#00880A}{t}}{5}-3$$ `=` `-6`
    $$\frac{\color{#00880A}{t}}{5}-3\color{#CC0000}{+3}$$ `=` `-6` `+3`
    $$\frac{\color{#00880A}{t}}{5}$$ `=` `-3` `-3+3` cancels out
    Next, remove `1/5` by multiplying both sides of the equation by `5`.
    $$\frac{\color{#00880A}{t}}{5}$$ `=` `-3`
    $$\frac{\color{#00880A}{t}}{5}\color{#CC0000}{\times5}$$ `=` `-3``xx5`
    `t` `=` `-15` `1/5 times5` cancels out
    Check our work
    To confirm our answer, substitute `t=-15` to the original equation.
    `t/5 -3` `=` `-6`
    `(-15)/5 -3` `=` `-6` Substitute `t=-15`
    `-3-3` `=` `-6`
    `-6` `=` `-6`
    Since the equation is true, the answer is correct.
    `t=-15`

    Hint
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  17. Question 17 of 21
    17. Question
    Solve
    `y/(-5) +6=-4`
    • `y=` (50)
    Correct

    Well Done!

    Incorrect

    Help Video
     
    Inverse Operations
    When moving a term to the other side of an equation, the operation is inversed.
    To solve for `y`, it needs to be alone on one side.
    Start by moving `6` to the other side by subtracting `6` from both sides of the equation.
    $$\frac{\color{#00880A}{y}}{-5}+6$$ `=` `-4`
    $$\frac{\color{#00880A}{y}}{-5}+6\color{#CC0000}{-6}$$ `=` `-4` `-6`
    $$\frac{\color{#00880A}{y}}{-5}$$ `=` `-10` `6-6` cancels out
    Next, remove `1/(-5)` by multiplying both sides of the equation by `-5`.
    $$\frac{\color{#00880A}{y}}{-5}$$ `=` `-10`
    $$\frac{\color{#00880A}{y}}{-5}\color{#CC0000}{\times-5}$$ `=` `-10``xx-5`
    `y` `=` `50` `1/(-5) times-5` cancels out
    Check our work
    To confirm our answer, substitute `y=50` to the original equation.
    `y/(-5) +6` `=` `-4`
    `50/(-5) +6` `=` `-4` Substitute `y=50`
    `-10+6` `=` `-4`
    `-4` `=` `-4`
    Since the equation is true, the answer is correct.
    `y=50`

    Hint
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  18. Question 18 of 21
    18. Question
    Solve for `x`
    `x/6+2=9`
    • `x=` (42)
    Correct

    Excellent!

    Incorrect

    Help Video
     
    To solve for `x`, get `x` by itself
    Subtract `2` from both sides of the equation
    `frac{x}{6}+2` `-2` `=` `9` `-2`
    `frac{x}{6}``+2` `-2` `=` `9` `-2` `2-2` cancels out
    `frac{x}{6}` `=` `7`
    Finally, multiply both sides of the equation by `6`
    `frac{x}{6}``times6` `=` `7``times6`
    `frac{6x}{6}` `=` `7``times6`
    `x` `=` `42` The coefficient `6/6` cancels out
    `x=42`

    Hint
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  19. Question 19 of 21
    19. Question
    Solve for `x`
    `x/7-2=3`
    • `x=` (35)
    Correct

    Nice Job!

    Incorrect

    Help Video
     
    To solve for `x`, get `x` by itself
    Add `2` to both sides of the equation
    `frac{x}{7}-2` `+2` `=` `3` `+2`
    `frac{x}{7}``-2` `+2` `=` `3` `+2` `-2+2` cancels out
    `frac{x}{7}` `=` `5`
    Finally, multiply both sides of the equation by `7`
    `frac{x}{7}``times7` `=` `5``times7` Multiply both sides by `7`
    `frac{7x}{7}` `=` `5``times7`
    `x` `=` `35` The coefficient `7/7` cancels out
    `x=35`

    Hint
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  20. Question 20 of 21
    20. Question
    Solve for `a`
    `a/10+4=12`
    • `a=` (80)
    Correct

    Well Done!

    Incorrect

    Help Video
     
    To solve for `a`, get `a` by itself
    Subtract `4` from both sides of the equation
    `frac{a}{10}+4` `-4` `=` `12` `-4`
    `frac{a}{10}``+4` `-4` `=` `12` `-4` `4-4` cancels out
    `frac{a}{10}` `=` `8`
    Finally, multiply both sides of the equation by `10`
    `frac{a}{10}``times10` `=` `8``times10`
    `frac{10a}{10}` `=` `8``times10`
    `a` `=` `80` The coefficient `10/10` cancels out
    `a=80`

    Hint
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  21. Question 21 of 21
    21. Question
    Solve for `v`
    `v/7 + 1=3`
    • `v=` (14)
    Correct

    Fantastic!

    Incorrect

    To solve for `v`, get `v` by itself
    Subtract `1` from both sides of the equation
    `v/7 + 1` `-1` `=` `3` `-1`
    `v/7``+1` `-1` `=` `3` `-1` `1-1` cancels out
    `v/7` `=` `2`
    Finally, multiply both sides of the equation by `7`
    `v/7``xx 7` `=` `2``xx 7`
    `(7v)/7` `=` `2``xx 7`
    `v` `=` `14` The coefficient `7/7` cancels out
    `v=14`

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