Back to Equations
Two Step Equations
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Question 1 of 21
1. Question
Solve`2m+8=12`- `m=` (2)
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Inverse Operations
When moving a term to the other side of an equation, the operation is inversed.To solve for `m`, it needs to be alone on one side.Start by moving `8` to the other side by subtracting `8` from both sides of the equation.`2``m` `+8` `=` `12` `2``m` `+8` `-8` `=` `12` `-8` `2``m` `=` `4` `8-8` cancels out Next, remove `2` by dividing both sides of the equation by `2`.`2``m` `=` `4` `2``m``-:2` `=` `4``-:2` `m` `=` `2` `2-:2` cancels out Check our workTo confirm our answer, substitute `m=2` to the original equation.`2m+8` `=` `12` `2(2)+8` `=` `12` Substitute `m=2` `4+8` `=` `12` `12` `=` `12` Since the equation is true, the answer is correct.`m=2`Hint
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Question 2 of 21
2. Question
Solve`5-2u=11`- `u=` (-3)
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Inverse Operations
When moving a term to the other side of an equation, the operation is inversed.To solve for `u`, it needs to be alone on one side.Start by moving `5` to the other side by subtracting `5` from both sides of the equation.`5-2``u` `=` `11` `5-2``u` `-5` `=` `11` `-5` `-2``u` `=` `6` `5-5` cancels out Next, remove `-2` by dividing both sides of the equation by `-2`.`-2``u` `=` `6` `-2``u``-:-2` `=` `6``-:-2` `u` `=` `-3` `-2-:-2` cancels out Check our workTo confirm our answer, substitute `u=-3` to the original equation.`5-2u` `=` `11` `5-2(-3)` `=` `11` Substitute `u=-3` `5+6` `=` `11` `11` `=` `11` Since the equation is true, the answer is correct.`u=-3`Hint
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Question 3 of 21
3. Question
Solve`4n-26=-2`- `n=` (6)
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Inverse Operations
When moving a term to the other side of an equation, the operation is inversed.To solve for `n`, it needs to be alone on one side.Start by moving `26` to the other side by adding `26` to both sides of the equation.`4``n` `-26` `=` `-2` `4``n` `-26` `+26` `=` `-2` `+26` `4``n` `=` `24` `-26+26` cancels out Next, remove `4` by dividing both sides of the equation by `4`.`4``n` `=` `24` `4``n``-:4` `=` `24``-:4` `n` `=` `6` `4-:4` cancels out Check our workTo confirm our answer, substitute `n=6` to the original equation.`4n-26` `=` `-2` `4(6)-26` `=` `-2` Substitute `n=6` `24-26` `=` `-2` `-2` `=` `-2` Since the equation is true, the answer is correct.`n=6`Hint
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Question 4 of 21
4. Question
Solve`3a+4=-8`- `a=` (-4)
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Great Work!
Incorrect
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Inverse Operations
When moving a term to the other side of an equation, the operation is inversed.To solve for `a`, it needs to be alone on one side.Start by moving `4` to the other side by subtracting `4` from both sides of the equation.`3``a` `+4` `=` `-8` `3``a` `+4` `-4` `=` `-8` `-4` `3``a` `=` `-12` `4-4` cancels out Next, remove `3` by dividing both sides of the equation by `3`.`3``a` `=` `-12` `3``a``-:3` `=` `-12``-:3` `a` `=` `-4` `3-:3` cancels out Check our workTo confirm our answer, substitute `a=-4` to the original equation.`3a+4` `=` `-8` `3(-4)+4` `=` `-8` Substitute `a=-4` `-12+4` `=` `-8` `-8` `=` `-8` Since the equation is true, the answer is correct.`a=-4`Hint
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Question 5 of 21
5. Question
Solve`-7x+8=-6`- `x=` (2)
Correct
Well Done!
Incorrect
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Inverse Operations
When moving a term to the other side of an equation, the operation is inversed.To solve for `x`, it needs to be alone on one side.Start by moving `8` to the other side by subtracting `8` from both sides of the equation.`-7``x` `+8` `=` `-6` `-7``x` `+8` `-8` `=` `-6` `-8` `-7``x` `=` `-14` `8-8` cancels out Next, remove `-7` by dividing both sides of the equation by `-7`.`-7``x` `=` `-14` `-7``x``-:-7` `=` `-14``-:-7` `x` `=` `2` `-7-:-7` cancels out Check our workTo confirm our answer, substitute `x=2` to the original equation.`-7x+8` `=` `-6` `-7(2)+8` `=` `-6` Substitute `x=2` `-14+8` `=` `-6` `-6` `=` `-6` Since the equation is true, the answer is correct.`x=2`Hint
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Question 6 of 21
6. Question
Solve`-2y-13=-11`- `y=` (-1)
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Fantastic!
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Inverse Operations
When moving a term to the other side of an equation, the operation is inversed.To solve for `y`, it needs to be alone on one side.Start by moving `13` to the other side by adding `13` to both sides of the equation.`-2``y` `-13` `=` `-11` `-2``y` `-13` `+13` `=` `-11` `+13` `-2``y` `=` `2` `-13+13` cancels out Next, remove `-2` by dividing both sides of the equation by `-2`.`-2``y` `=` `2` `-2``y``-:-2` `=` `2``-:-2` `y` `=` `-1` `-2-:-2` cancels out Check our workTo confirm our answer, substitute `y=-1` to the original equation.`-2y-13` `=` `-11` `-2(-1)-13` `=` `-11` Substitute `y=-1` `2-13` `=` `-11` `-11` `=` `-11` Since the equation is true, the answer is correct.`y=-1`Hint
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Question 7 of 21
7. Question
Solve for `x``2x+4=16`- `x=` (6)
Correct
Nice Job!
Incorrect
Help VideoTo solve for `x`, get `x` by itselfSubtract `4` from both sides of the equation`2x+4` `-4` `=` `16` `-4` `2x``+4``-4` `=` `16` `-4` `4-4` cancels out `2x` `=` `12` Finally, divide both sides of the equation by `2``2x``divide2` `=` `12``divide2` `2``x``divide2` `=` `12``divide2` `times2divide2` cancels out `x` `=` `6` `x=6`Hint
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Question 8 of 21
8. Question
Solve for `x``1-3x=7`- `x=` (-2)
Correct
Fantastic!
Incorrect
Help VideoTo solve for `x`, get `x` by itselfSubtract `1` from both sides of the equation`1-3x` `-1` `=` `7` `-1` `1``-3x` `-1` `=` `7` `-1` `1-1` cancels out `-3x` `=` `6` Finally, divide both sides of the equation by `-3``-3x``divide(-3)` `=` `6``divide(-3)` `-3``x``divide(-3)` `=` `6``divide(-3)` `times(-3)divide(-3)` cancels out `x` `=` `-2` `x=-2`Hint
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Question 9 of 21
9. Question
Solve for `x``3x+7=19`- `x=` (4)
Correct
Correct!
Incorrect
To solve for `x`, get `x` by itselfSubtract `7` from both sides of the equation`3x+7` `-7` `=` `19` `-7` `3x``+7` `-7` `=` `19` `-7` `7-7` cancels out `3x` `=` `12` Finally, divide both sides of the equation by `3``3x``divide3` `=` `12``divide3` `3``x``divide3` `=` `12``divide3` `times3divide3` cancels out `x` `=` `4` `x=4` -
Question 10 of 21
10. Question
Solve for `m``2m+9=23`- `m=` (7)
Correct
Great Work!
Incorrect
Help VideoTo solve for `m`, get `m` by itselfSubtract `9` from both sides of the equation`2m+9` `-9` `=` `23` `-9` `2m``+9` `-9` `=` `23` `-9` `9-9` cancels out `2m` `=` `14` Finally, divide both sides of the equation by `2``2m``divide2` `=` `14``divide2` `2``m``divide2` `=` `14``divide2` `times2divide2` cancels out `m` `=` `7` `m=7`Hint
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Question 11 of 21
11. Question
Solve for `a``3a+5=-10`- `a=` (-5)
Correct
Keep Going!
Incorrect
Help VideoTo solve for `a`, get `a` by itselfSubtract `5` from both sides of the equation`3a+5` `-5` `=` `-10` `-5` `3a``+5` `-5` `=` `-10` `-5` `5-5` cancels out `3a` `=` `-15` Finally, divide both sides of the equation by `3``3a``divide3` `=` `-15``divide3` `3``a``divide3` `=` `-15``divide3` `times3divide3` cancels out `a` `=` `-5` `a=-5`Hint
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Question 12 of 21
12. Question
Solve for `p``-1+5p=-16`- `p=` (-3)
Correct
Excellent!
Incorrect
To solve for `p`, get `p` by itselfAdd `1` to both sides of the equation`-1+5p` `+1` `=` `-16` `+1` `-1``+5p` `+1` `=` `-16` `+1` `-1+1` cancels out `5p` `=` `-15` Finally, divide both sides of the equation by `5``5p``-:5` `=` `-15``-:5` `5``p``divide5` `=` `-15``-:5` `times5divide5` cancels out `p` `=` `-3` `p=-3` -
Question 13 of 21
13. Question
Solve for `r``-4r-1=31`- `r=` (-8)
Correct
Well Done!
Incorrect
To solve for `r`, get `r` by itselfAdd `1` to both sides of the equation`-4r-1``+1` `=` `31``+1` `-4r``-1``+1` `=` `32` `-1+1` cancels out `-4r` `=` `32` Finally, divide both sides of the equation by `-4``-4r``divide -4` `=` `32``divide -4` `-4``r``divide -4` `=` `-8` `-4 divide -4` cancels out `r` `=` `-8` `r=-8` -
Question 14 of 21
14. Question
Solve`x/3 +4=7`- `x=` (9)
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Good Job!
Incorrect
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Inverse Operations
When moving a term to the other side of an equation, the operation is inversed.To solve for `x`, it needs to be alone on one side.Start by moving `4` to the other side by subtracting `4` from both sides of the equation.$$\frac{\color{#00880A}{x}}{3}+4$$ `=` `7` $$\frac{\color{#00880A}{x}}{3}+4\color{#CC0000}{-4}$$ `=` `7` `-4` $$\frac{\color{#00880A}{x}}{3}$$ `=` `3` `4-4` cancels out Next, remove `1/3` by multiplying both sides of the equation by `3`.$$\frac{\color{#00880A}{x}}{3}$$ `=` `3` $$\frac{\color{#00880A}{x}}{3}\color{#CC0000}{\times3}$$ `=` `3``xx3` `x` `=` `9` `1/3 times3` cancels out Check our workTo confirm our answer, substitute `x=9` to the original equation.`x/3 +4` `=` `7` `9/3 +4` `=` `7` Substitute `x=9` `3+4` `=` `7` `7` `=` `7` Since the equation is true, the answer is correct.`x=9`Hint
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Question 15 of 21
15. Question
Solve`x/7 +3=-2`- `x=` (-35)
Correct
Great Work!
Incorrect
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Inverse Operations
When moving a term to the other side of an equation, the operation is inversed.To solve for `x`, it needs to be alone on one side.Start by moving `3` to the other side by subtracting `3` from both sides of the equation.$$\frac{\color{#00880A}{x}}{7}+3$$ `=` `-2` $$\frac{\color{#00880A}{x}}{7}+3\color{#CC0000}{-3}$$ `=` `-2` `-3` $$\frac{\color{#00880A}{x}}{7}$$ `=` `-5` `3-3` cancels out Next, remove `1/7` by multiplying both sides of the equation by `7`.$$\frac{\color{#00880A}{x}}{7}$$ `=` `-5` $$\frac{\color{#00880A}{x}}{7}\color{#CC0000}{\times7}$$ `=` `-5``xx7` `x` `=` `-35` `1/7 times7` cancels out Check our workTo confirm our answer, substitute `x=-35` to the original equation.`x/7 +3` `=` `-2` `(-35)/7 +3` `=` `-2` Substitute `x=-35` `-5+3` `=` `-2` `-2` `=` `-2` Since the equation is true, the answer is correct.`x=-35`Hint
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Question 16 of 21
16. Question
Solve`t/5 -3=-6`- `t=` (-15)
Correct
Excellent!
Incorrect
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Inverse Operations
When moving a term to the other side of an equation, the operation is inversed.To solve for `t`, it needs to be alone on one side.Start by moving `3` to the other side by adding `3` to both sides of the equation.$$\frac{\color{#00880A}{t}}{5}-3$$ `=` `-6` $$\frac{\color{#00880A}{t}}{5}-3\color{#CC0000}{+3}$$ `=` `-6` `+3` $$\frac{\color{#00880A}{t}}{5}$$ `=` `-3` `-3+3` cancels out Next, remove `1/5` by multiplying both sides of the equation by `5`.$$\frac{\color{#00880A}{t}}{5}$$ `=` `-3` $$\frac{\color{#00880A}{t}}{5}\color{#CC0000}{\times5}$$ `=` `-3``xx5` `t` `=` `-15` `1/5 times5` cancels out Check our workTo confirm our answer, substitute `t=-15` to the original equation.`t/5 -3` `=` `-6` `(-15)/5 -3` `=` `-6` Substitute `t=-15` `-3-3` `=` `-6` `-6` `=` `-6` Since the equation is true, the answer is correct.`t=-15`Hint
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Question 17 of 21
17. Question
Solve`y/(-5) +6=-4`- `y=` (50)
Correct
Well Done!
Incorrect
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Inverse Operations
When moving a term to the other side of an equation, the operation is inversed.To solve for `y`, it needs to be alone on one side.Start by moving `6` to the other side by subtracting `6` from both sides of the equation.$$\frac{\color{#00880A}{y}}{-5}+6$$ `=` `-4` $$\frac{\color{#00880A}{y}}{-5}+6\color{#CC0000}{-6}$$ `=` `-4` `-6` $$\frac{\color{#00880A}{y}}{-5}$$ `=` `-10` `6-6` cancels out Next, remove `1/(-5)` by multiplying both sides of the equation by `-5`.$$\frac{\color{#00880A}{y}}{-5}$$ `=` `-10` $$\frac{\color{#00880A}{y}}{-5}\color{#CC0000}{\times-5}$$ `=` `-10``xx-5` `y` `=` `50` `1/(-5) times-5` cancels out Check our workTo confirm our answer, substitute `y=50` to the original equation.`y/(-5) +6` `=` `-4` `50/(-5) +6` `=` `-4` Substitute `y=50` `-10+6` `=` `-4` `-4` `=` `-4` Since the equation is true, the answer is correct.`y=50`Hint
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Question 18 of 21
18. Question
Solve for `x``x/6+2=9`- `x=` (42)
Correct
Excellent!
Incorrect
Help VideoTo solve for `x`, get `x` by itselfSubtract `2` from both sides of the equation`frac{x}{6}+2` `-2` `=` `9` `-2` `frac{x}{6}``+2` `-2` `=` `9` `-2` `2-2` cancels out `frac{x}{6}` `=` `7` Finally, multiply both sides of the equation by `6``frac{x}{6}``times6` `=` `7``times6` `frac{6x}{6}` `=` `7``times6` `x` `=` `42` The coefficient `6/6` cancels out `x=42`Hint
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Question 19 of 21
19. Question
Solve for `x``x/7-2=3`- `x=` (35)
Correct
Nice Job!
Incorrect
Help VideoTo solve for `x`, get `x` by itselfAdd `2` to both sides of the equation`frac{x}{7}-2` `+2` `=` `3` `+2` `frac{x}{7}``-2` `+2` `=` `3` `+2` `-2+2` cancels out `frac{x}{7}` `=` `5` Finally, multiply both sides of the equation by `7``frac{x}{7}``times7` `=` `5``times7` Multiply both sides by `7` `frac{7x}{7}` `=` `5``times7` `x` `=` `35` The coefficient `7/7` cancels out `x=35`Hint
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Question 20 of 21
20. Question
Solve for `a``a/10+4=12`- `a=` (80)
Correct
Well Done!
Incorrect
Help VideoTo solve for `a`, get `a` by itselfSubtract `4` from both sides of the equation`frac{a}{10}+4` `-4` `=` `12` `-4` `frac{a}{10}``+4` `-4` `=` `12` `-4` `4-4` cancels out `frac{a}{10}` `=` `8` Finally, multiply both sides of the equation by `10``frac{a}{10}``times10` `=` `8``times10` `frac{10a}{10}` `=` `8``times10` `a` `=` `80` The coefficient `10/10` cancels out `a=80`Hint
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Question 21 of 21
21. Question
Solve for `v``v/7 + 1=3`- `v=` (14)
Correct
Fantastic!
Incorrect
To solve for `v`, get `v` by itselfSubtract `1` from both sides of the equation`v/7 + 1` `-1` `=` `3` `-1` `v/7``+1` `-1` `=` `3` `-1` `1-1` cancels out `v/7` `=` `2` Finally, multiply both sides of the equation by `7``v/7``xx 7` `=` `2``xx 7` `(7v)/7` `=` `2``xx 7` `v` `=` `14` The coefficient `7/7` cancels out `v=14`
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- One Step Equations – Add and Subtract
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